Linux cli command frexpf

➡ A Linux man page (short for manual page) is a form of software documentation found on Linux and Unix-like operating systems. This man-page explains the command frexpf and provides detailed information about the command frexpf, system calls, library functions, and other aspects of the system, including usage, options, and examples of _. You can access this man page by typing man followed by the frexpf.

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NAME 🖥️ frexpf 🖥️

convert floating-point number to fractional and integral components

LIBRARY

Math library (libm, -lm)

SYNOPSIS

#include <math.h>
double frexp(double x, int *exp);
float frexpf(float x, int *exp);
long double frexpl(long double x, int *exp);

Feature Test Macro Requirements for glibc (see feature_test_macros(7)):

frexpf(), frexpl():

    _ISOC99_SOURCE || _POSIX_C_SOURCE >= 200112L
        || /* Since glibc 2.19: */ _DEFAULT_SOURCE
        || /* glibc <= 2.19: */ _BSD_SOURCE || _SVID_SOURCE

DESCRIPTION

These functions are used to split the number x into a normalized fraction and an exponent which is stored in exp.

RETURN VALUE

These functions return the normalized fraction. If the argument x is not zero, the normalized fraction is x times a power of two, and its absolute value is always in the range 1/2 (inclusive) to 1 (exclusive), that is, [0.5,1).

If x is zero, then the normalized fraction is zero and zero is stored in exp.

If x is a NaN, a NaN is returned, and the value of *exp is unspecified.

If x is positive infinity (negative infinity), positive infinity (negative infinity) is returned, and the value of *exp is unspecified.

ERRORS

No errors occur.

ATTRIBUTES

For an explanation of the terms used in this section, see attributes(7).

InterfaceAttributeValue

frexp(), frexpf(), frexpl()

Thread safetyMT-Safe

STANDARDS

C11, POSIX.1-2008.

HISTORY

C99, POSIX.1-2001.

The variant returning double also conforms to SVr4, 4.3BSD, C89.

EXAMPLES

The program below produces results such as the following:

$ ./a.out 2560
frexp(2560, &e) = 0.625: 0.625 * 2^12 = 2560
$ ./a.out -4
frexp(-4, &e) = -0.5: -0.5 * 2^3 = -4

Program source

#include <float.h>
#include <math.h>
#include <stdio.h>
#include <stdlib.h>
int
main(int argc, char *argv[])
{
    double x, r;
    int exp;
    x = strtod(argv[1], NULL);
    r = frexp(x, &exp);
    printf("frexp(%g, &e) = %g: %g * %d^%d = %g

“, x, r, r, 2, exp, x); exit(EXIT_SUCCESS); }

SEE ALSO

ldexp(3), modf(3)

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